Aaron Rodgers will make $10M guaranteed with Steelers, wear No. 8

Gerry Dulac, Pittsburgh Post-Gazette on Jun 7, 2025

Published in Football

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PITTSBURGH — Aaron Rodgers’ one-year deal with the Steelers is for $13.65 million with $10 million guaranteed and includes another $5.85 million in incentives, sources have told the Pittsburgh Post-Gazette.

Rodgers, 41, a four-time NFL MVP, arrived at the Steelers facility in the South Side on Saturday morning to sign the contract, which potentially can be worth $19.5 million.

Rodgers will take part in the team’s first day of minicamp on Tuesday, at which time he is expected to meet with the media.

The Steelers were informed by Rodgers on Thursday that he planned to sign a contract and take part in the team’s minicamp. It ended a two-month long process in which the Steelers always believed the league’s seventh-all-time leading passer would sign with them.

But it continues the revolving door that has existed for the Steelers since Ben Roethlisberger retired after the 2021 season. Barring injury, Rodgers will be the fourth different quarterback to start the season opener in the past four years.

The team also announced on social media that Rodgers will wear No. 8, the same number he wore with the Jets. Rodgers wore No. 12 during the entirety of his Packers career, but that number belonged to Terry Bradshaw in Pittsburgh.

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